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6n^2+n-26=0
a = 6; b = 1; c = -26;
Δ = b2-4ac
Δ = 12-4·6·(-26)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-25}{2*6}=\frac{-26}{12} =-2+1/6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+25}{2*6}=\frac{24}{12} =2 $
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